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The scaredy cats saw each other when they were 10 meters apart. The cats
immediately started to run in opposite directions, each at the speed of 80 meters per
minute. How far apart will the cats be in 3 minutes?

Sagot :

semsee45

Answer:

490 m

Step-by-step explanation:

run speed = 80 m/min

Therefore, distance ran in 3 minutes = 80 x 3 = 240 m

As the cats are running in opposite directions, if they started from the same point, they would be 240 + 240 = 480 m apart.

However, as they started at a point 10 m apart, we need to add 10 to 480 to calculate the final distance:  480 + 10 = 490m.

Therefore, the cats will be 490m apart after 3 minutes of running in opposite directions (with an initial starting point of 10m apart).

Using a linear function, it is found that the cats will be 490 meters apart in 3 minutes.

What is a linear function?

A linear function is modeled by:

[tex]y = mx + b[/tex]

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0.

In this problem:

  • Initially, they are 10 meters apart, hence b = 10.
  • They go in opposite directions, each at a speed of 80 meters per minute, hence, each minute, they get 160 meters apart, which means that m = 160.

Hence, the equation for their distance after x minutes is:

d(x) = 160x + 10

For 3 minutes, we have x = 3, hence:

d(3) = 160(3) + 10 = 490.

The cats will be 490 meters apart in 3 minutes.

You can learn more about linear functions at https://brainly.com/question/24282972

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