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Find the first 4 terms of:
Σ ()
N=1
(9 n - 6).
Help please

Sagot :

A1 = 9 × 1 - 6 = 3

A2 = 18 - 6 = 12

A3 = 27 - 6 = 21

A4 = 36 - 6 = 30.

Step-by-step explanation:

Σ ( 9n - 6 ) , n = 1

An = general term.

let Σ (An) = Σ (9n-6)

An = 9n-6

to determine the terms, plug in the value of n into the general term(An)

If you're asked for the 1st term then n = 1

if you're asked for the 2nd term then n = 2. and so forth.

To find the 1st 4 terms, just plug in 1 up to 4 into n bit by bit.

An = 9n - 6

A1 = 9 × 1 - 6 = 3

A2 = 18 - 6 = 12

A3 = 27 - 6 = 21

A4 = 36 - 6 = 30. done.

write the terms from 1 to 4 like this :

{ A1, A2, A3, A4 } = { 3, 12, 21, 30 }.