Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Find the midpoint of the line segment with end coordinates of: (-4,-2) and (-2, -10)​

Find The Midpoint Of The Line Segment With End Coordinates Of 42 And 2 10 class=

Sagot :

Answer:

(-3,-6)

Step-by-step explanation:

midpoint formula : [tex](\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )[/tex]

where the x and y values derive from the given points

The points given are (-4,-2) and (-2,-10)

The first step is to assign variables

first coordinate : (x1,y1) = (-4,-2) so x1 = -4 and y1 = -2

second coordinate : (x2,y2) = (-2,-10) so x2 = -2 and y2 = -10

Next we plug in these values into the formula

Recall formula : [tex](\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )[/tex]

x1 = -4 , x2 = -2 , y1 - 2 and y2 = - 10

plug in values

[tex](\frac{-4+(-2))}{2} ,\frac{-2+(-10)}{2} )[/tex]

simplify numerators : -4 + -2 = -6 and -2 + -10 = -12

[tex](\frac{-6}{2} ,\frac{-12}{2} )[/tex]

simplify fractions : -6/2 = -3 and -12/2 = -6

the midpoint is (-3,-6)