baib08brown
Answered

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which of these systems would be best solved by using the elimination method? (Check all that apply)

options:

1.) 14x-8y=34
3x+8y=12

2.) 5x-2y=65
8x+9y=4

3.) y=2x-3
2x+5y=4

4.) -4x+2y=7
4x+8y=23

Which Of These Systems Would Be Best Solved By Using The Elimination Method Check All That Apply Options 1 14x8y34 3x8y12 2 5x2y65 8x9y4 3 Y2x3 2x5y4 4 4x2y7 4x class=

Sagot :

SenorMathWiz

Answer:

option 1 and 4

Step-by-step explanation:

The elimination method should be used when there are two variables with the same number in front of them but different signs.

In the first system, the first equation has -8y while the second one has 8y.

Both equations have an 8y with different signs therefore using the elimination method would be most logical.

In the fourth system, the first equation has a -4x while the second one has 4x.

Both equations have 4x with different signs therefore using the elimination method would be most logical

Reasons it can't be the other options :

In the second system, no variable has the same number before it so no variable can be eliminated unless you multiply the equations by a common multiple. The best method for this system would be graphing

In the third system y is defined by an expression therefore using the substitution method is the most logical approach.

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