To find the time that it will take for the ball to hit the ground we need to solve:
p(t) = (-4.9 m/s^2)*t^2 + (15m/s)*t + 1m = 0m.
¿How to find the motion equation for the ball?
We should start by the easier part, which is acceleration.
The only force acting on the ball will be the gravitational force, this means that the acceleration of the ball is -9.8 m/s^2
a(t) = -9.8 m/s^2
To get the velocity, we integrate over time, and remember that the constant of integration is equal to the initial velocity, which we already know is equal to 15m/s.
v(t) = (-9.8 m/s^2)*t + 15m/s.
To get the position equation we integrate again, this time the constant of integration is the initial position, which is 1m.
p(t) = (1/2)(-9.8 m/s^2)*t^2 + (15m/s)*t + 1m
p(t) = (-4.9 m/s^2)*t^2 + (15m/s)*t + 1m
The ball will hit the ground when the position is equal to zero, so we need to solve:
p(t) = (-4.9 m/s^2)*t^2 + (15m/s)*t + 1m = 0m.
If you want to learn more about motion equations, you can read:
https://brainly.com/question/605631
