Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
Hello!
When the rock is dropped, it only contains Gravitational Potential Energy, and when it hits the ground, it contains Kinetic Energy.
So:
PE = KE
[tex]\large\boxed{mgh = \frac{1}{2}mv^2}[/tex]
We can rearrange to solve for velocity. Cancel out mass and solve.
[tex]gh = \frac{1}{2}v^2\\\\2gh = v^2\\\\v = \sqrt{2gh}[/tex]
Plug in the givens:
[tex]v = \sqrt{2(9.8)(4)} = \boxed{8.85 \frac{m}{s}}[/tex]
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.