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. A rock is dropped from a height of 4 m. How fast is it going when it hits the ground? The rock has a mass of 2 kg. (Hint: MEi = MEf)

Sagot :

leena

Hello!

When the rock is dropped, it only contains Gravitational Potential Energy, and when it hits the ground, it contains Kinetic Energy.

So:

PE = KE
[tex]\large\boxed{mgh = \frac{1}{2}mv^2}[/tex]

We can rearrange to solve for velocity. Cancel out mass and solve.


[tex]gh = \frac{1}{2}v^2\\\\2gh = v^2\\\\v = \sqrt{2gh}[/tex]

Plug in the givens:


[tex]v = \sqrt{2(9.8)(4)} = \boxed{8.85 \frac{m}{s}}[/tex]

Answer:

8.85 m/s

Explanation: