Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

A small ball of mass 0.75 kg is attached to one end of a 1.25-m-long massless rod, and the other end of the rod is hung from a pivot. When the resulting pendulum is 30o from the vertical,what is the magnitude of the gravitational torque calculated about the pivot

Sagot :

leena

Hi there!

Recall the equation for Torque:
[tex]\large\boxed{\Sigma \tau = rFsin\phi}[/tex]

In words, the torque is the force multiplied by the distance from the LINE OF ACTION to the PIVOT POINT.

In this instance:

F = Mg = 0.75 · 9.8 = 7.35 N

r = 1.25 m

sin(30) = 0.5

Plug in the values:

[tex]\Sigma \tau = (1.25)(7.35)(0.5) = \boxed{4.59 Nm}[/tex]

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.