The average force on the squid during the ejection of 0.60 kg of water at a velocity of 15.0 m/s in 0.15 seconds is 60 N.
We can calculate the average force with the average acceleration as follows:
[tex] F = m\overline{a} [/tex] (1)
Where:
The average acceleration is given by the change of velocity in an interval of time
[tex] \overline{a} = \frac{v_{f} - v_{i}}{t_{f} - t_{i}} [/tex] (2)
Where:
Now we can find the average force after entering equation (2) into (1)
[tex] F = m(\frac{v_{f} - v_{i}}{t_{f} - t_{i}}) = 0.60 kg(\frac{15.0 m/s - 0}{0.15 s}) = 60 N [/tex]
Therefore, the average force on the squid during the propulsion is 60 N.
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I hope it helps you!
