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Sagot :
Approximately how far out from the cliff is Aditya's boat is 63.64ft.
Distance
Given:
Standing atop a cliff above the water =35 ft
Standing at edge of the cliff=10ft
Eye level=5.5ft
Hence:
AE/CD=BC/DE
5.5/35=10/DE
AE=35×10/5.5
AE=350/5.5
AE=63.636ft
AE=63.64ft (Approximately)
Inconclusion approximately how far out from the cliff is Aditya's boat is 63.64ft.
Learn more about distance here:https://brainly.com/question/4931057
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