Answered

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You are playing a board game with a spinner that has numbers 1, 2, 3, and 4 on
it. You get to spin the spinner twice. What is the probability that you land on
number 2 given that your first spin landed on number 1?

Sagot :

semsee45

Answer:

1/4

Step-by-step explanation:

Let x = number the spinner lands on

P(X = 1) = 1/4

P(X = 2) = 1/4

P(X = 3) = 1/4

P(X = 4) = 1/4

The spins are independent events as their probabilities are not affected by whether or not the other event happens

Therefore, the probability that you land on a number 2 given that your first spin landed on number 1 is still 1/4

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