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Find an equation for the nth term of the arithmetic sequence.
a10 = 32, a12 = 106

an = -301 + 37(n - 1)
an = -301 + 37(n - 2)
an = -301 + 37(n + 1)
an = -301 - 37(n + 1)

Sagot :

Answer:

[tex]a_n=-301 +37(n-1)[/tex]

Step-by-step explanation:

arithmetic sequence formula:  [tex]a_n=a +(n-1)d[/tex]

where [tex]a[/tex] is the first term and [tex]d[/tex] is the common difference

Given:

  [tex]a_{10}=32[/tex]

⇒ [tex]a +(10-1)d=32[/tex]

⇒ [tex]a+9d=32[/tex]

Given:

    [tex]a_{12}=106[/tex]

⇒ [tex]a +(12-1)d=106[/tex]

⇒ [tex]a+11d=106[/tex]

Rearrange the first equation to make [tex]a[/tex] the subject:

a = 32 - 9d

Now substitute into the second equation and solve for [tex]d[/tex]

    (32 - 9d) + 11d = 106

⇒ 32 + 2d = 106

⇒ 2d = 106 - 32 = 74

⇒ d = 74 ÷ 2 = 37

Substitute found value of [tex]d[/tex] into the first equation and solve for [tex]a[/tex]:

a + (9 x 37) = 32

a + 333 = 32

a = 32 - 333 = -301

Therefore, the equation is: [tex]a_n=-301 +37(n-1)[/tex]