At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
This question involves the concepts of density, volume, and mass.
The approximate diameter of a magnesium atom is "3.55 x 10⁻¹⁰ m".
STEP 1 (FINDING MASS OF INDIVIDUAL ATOM)
It is given that:
Mass of one mole = 24 grams
Mass of 6 x 10²³ atoms = 24 grams
Mass of 1 atom = [tex]\frac{24\ grams}{6\ x\ 10^{23}\ atoms}[/tex] = 4 x 10⁻²³ grams
STEP 2 (FINDING VOLUME OF A SINGLE ATOM)
[tex]\rho = \frac{m}{V}\\\\V=\frac{m}{\rho}[/tex]
where,
- [tex]\rho[/tex] = density = 1.7 grams/cm³
- m = mass of single atom = 4 x 10⁻²³ grams
- V = volume of single atom = ?
Therefore,
[tex]V=\frac{4\ x\ 10^{-23}\ grams}{1.7\ grams/cm^3}[/tex]
V = 2.35 x 10⁻²³ cm³
STEP 3 (FINDING DIAMETER OF ATOM)
The atom is in a spherical shape. Hence, its Volume can be given as follows:
[tex]V =\frac{\pi d^3}{6}\\\\d=\sqrt[3]{ \frac{6V}{\pi}}\\\\d=\sqrt[3]{ \frac{6(2.35\ x\ 10^{-23}\ cm^3)}{\pi}}[/tex]
d = 0.355 x 10⁻⁷ cm = 3.55 x 10⁻¹⁰ m
Learn more about density here:
https://brainly.com/question/952755
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.