Answered

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The sum of two consecutive integers
is sixty-five. Find the smaller of the
two numbers.

Sagot :

renknee

Answer:

32

Step-by-step explanation:

We can write an algebraic equation to solve this situation: [tex]x + x + 1 = 65[/tex], where x = first integer (small number) and x + 1 = the following integer.

Step 1: Combine like terms.

  • [tex](x+x)+1=65[/tex]
  • [tex]2x + 1 = 65[/tex]

Step 2: Subtract 1 from both sides.

  • [tex]2x + 1 - 1 = 65 - 1[/tex]
  • [tex]2x = 64[/tex]

Step 3: Divide both sides by 2.

  • [tex]2x/2 = 64/2[/tex]
  • [tex]x = 32[/tex]

Therefore, the smaller number is 32 while the larger number is 33.

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