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Sagot :
Answer:
The distance of the run is 10 miles
The distance of the bicycle race is 69 miles
Step-by-step explanation:
Let:
- r = the distance for the run
- 79 - r = the distance for the bicycle race
- t = the time of the run
- 5 - t = the time of the bicycle race
The run: r = 5t
The bicycle race: 79 - r = 23(5 - t)
Simplify the bicycle race:
- 79 - r = 115 - 23t
- -r = 36 - 23t
- r = 23t - 36
Now we have two equations set up for r
- r = 5t
- r = 23t - 36
We know that r = r, so 5t must equal 23t - 36
- 5t = 23t - 36
- 5t + 36 = 23t
- 36 = 18t
- t = 2
Now we know that the run took 2 hours.
Plug it back into the equation for the run to find the distance for the run
- r = 5t
- r = 5(2)
- r = 10
The run is 10 miles
To solve for the bicycle race, we simply subtract 10 from 79, because we know that the two distances combined are 79.
- 79 - 10 = 69
The bicycle race is 69 miles.
-Chetan K
Answer:
- run: 10 miles
- bike race: 69 miles
Step-by-step explanation:
Let r represent the distance run. Then 79-r is the distance biked. The total time is ...
time = distance/speed
5 = (r/5) +(79-r)/23 . . . . sum of time running and time biking
575 = 23r +5(79 -r) . . . . multiply by 115
180 = 18r . . . . . . . . . . . . . subtract 395
10 = r . . . . . . . . . . . divide by 18
79-r = 69 . . . . . . distance biking
The distance of the run is 10 miles; the bicycle race is 69 miles.
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