Answered

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A woman has a total of $9,000 to invest. She invests part of the money in an account that pays 7 % per year and
the rest in an account that pays 11 % per year. If the interest earned in the first year is $790, how much did she
invest in each account?

Sagot :

MangoSSlay1231

Answer:

Hi! I believe this is your answer:

$750

Step by step explanation:

interest + interest      = total interest

0.08*x   + 0.09*(9000-x) = 750    dollars

0.08x + 810 - 0.09x = 750

-0.01x = 750 - 810 = -60  ====>  x = %28-60%29%2F%28-0.01%29 = 6000.

Final answer:  

$6000 was invested at 8%.  The rest   9000-6000 = 3000 dollars were invested at 9%.

Check.   0.08*6000 + 0.09*3000 = 480 + 270 = 750 dollars.

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