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Sagot :
We have that the Number of stitches per sec and he mass of oscillation motion is mathematically given as
a) Nt=25stitches per sec
b) m=2.033e-5kg
Number of stitches per sec and he mass of oscillation motion
Question Parameters:
This sewing machine is capable of stitching 1,500 stiches in one minute.
If the sewing machine has a spring constant of 0.5 N/m,
Generally the equation for the Number of stitches per sec is mathematically given as
Nt=N/t
Therefore
Nt=1500/60
Nt=25stitches per sec
b)
Generally the equation for the Time t is mathematically given as
[tex]T=2\pi\sqrt{\frac{m}{k}}[/tex]
Therefore
[tex]0.04=2\pi\sqrt{\frac{m}{0.5}}\\\\m=\frac{0.5*0.04^2}{4\pi^2}[/tex]
m=2.033e-5kg
For more information on Mass visit
https://brainly.com/question/15959704
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