Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
So, the speed of the ball after 2 seconds after free fall is 20 m/s.
Introduction
Hi ! I'm Deva from Brainly Indonesia. In this material, we can call this event "Free Fall Motion". There are two conditions for free fall motion, namely falling (from top to bottom) and free (without initial velocity). Because the question only asks for the final velocity of the ball, in fact, we may use the formula for the relationship between acceleration and change in velocity and time. In general, this relationship can be expressed in the following equation :
[tex] \boxed{\sf{\bold{a = \frac{v_2 - v_1}{t}}}} [/tex]
With the following conditions :
- a = acceleration (m/s²)
- [tex] \sf{v_2} [/tex] = speed after some time (m/s)
- [tex] \sf{v_1} [/tex] = initial speed (m/s)
- t = interval of time (s)
Problem Solving
We know that :
- a = acceleration = 9,8 m/s² >> because the acceleration of a falling object is following the acceleration of gravity (g).
- [tex] \sf{v_1} [/tex] = initial speed = 0 m/s >> the keyword is free fall
- t = interval of time = 2 s
What was asked :
- [tex] \sf{v_2} [/tex] = speed after some time = ... m/s
Step by step :
[tex] \sf{a = \frac{v_2 - v_1}{t}} [/tex]
[tex] \sf{(a \times t) + v_1 = v_2} [/tex]
[tex] \sf{(10 \times 2) + 0 = v_2} [/tex]
[tex] \boxed{\sf{v_2 = 20 \: m/s}} [/tex]
So, the speed of the ball after 2 seconds after free fall is 20 m/s.
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.