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the graph represents the value y of a boat after x years. find the value of the boat after 2 years and after 8 years.

The Graph Represents The Value Y Of A Boat After X Years Find The Value Of The Boat After 2 Years And After 8 Years class=

Sagot :

  • (0,30)
  • (1,24)

Find slope

[tex]\\ \tt\hookrightarrow m=\dfrac{24-30}{1-0}=\dfrac{-6}{1}=-6[/tex]

Equation of line in point slope form

[tex]\\ \tt\hookrightarrow y-y_1=m(x-x_1)[/tex]

[tex]\\ \tt\hookrightarrow y-30=-6(x-0)[/tex]

[tex]\\ \tt\hookrightarrow y-30=-6x[/tex]

  • Convert to slope intercept form y=mx+b

[tex]\\ \tt\hookrightarrow y=-6x+30[/tex]

After 2years:-

[tex]\\ \tt\hookrightarrow y=-6(2)+30=-12+30=18000\$[/tex]

After 8years:-

[tex]\\ \tt\hookrightarrow y=-6(8)+30=-48+30=-18[/tex]

  • But We can see that line is parallel to x axis right after x=7

So

  • The value will be equal to y axis i.e y=5

So the value after 8years is 5000$

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