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Use Pythagorean Theorem a? + b2 = to find the value of x. Round to the nearest tenth (one decimal place).
x=1
19.1
1
30.5

Use Pythagorean Theorem A B2 To Find The Value Of X Round To The Nearest Tenth One Decimal Place X1 191 1 305 class=

Sagot :

VirαtKσhli

Answer : 23.77

Pythagoras theorem states that in any right angled triangle , the sum of squares of base and perpendicular is equal to the square of hypotenuse .

  • Here in the given figure , hypotenuse is 30.5 and perpendicular is 19.1 .

[tex]\sf\longrightarrow (base)^2+(perpendicular)^2=hypotenuse^2\\[/tex]

  • Substituting the respective values,

[tex]\sf\longrightarrow x^2 +(19.1)^2 = (30.5)^2 \\[/tex]

[tex]\sf\longrightarrow x^2 + 364.81 = 930.25 \\[/tex]

[tex]\sf\longrightarrow x^2 = 930.25 -364.81\\[/tex]

[tex]\sf\longrightarrow x^2 = 565.44\\[/tex]

[tex]\sf\longrightarrow x=\sqrt{565.44} \\[/tex]

[tex]\sf\longrightarrow \underline{\boxed{\bf base (x) = 23.77 }} \\[/tex]

Let me know if you have any queries in the comment section !

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