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Sagot :

[tex]\qquad[/tex] ☀️[tex]\pink{\bf{ {Answer = \: \: 85.57g }}} [/tex]

Molar mass of [tex]\bf Cu_2O [/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf 63.546 \times 2 +16[/tex]

[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf 143.092 g}[/tex]

As we know

1 mol =[tex] \bf 6.02×10^{23} [/tex] formula units

1 mol[tex]\bf Cu_2O [/tex] = 143.092 g = [tex] \bf 6.02×10^{23} [/tex]formula units

Henceforth –

[tex]\bf 3.60×10^{23} [/tex] formula units [tex]\bf Cu_2O [/tex]–

[tex]\qquad[/tex] [tex]\sf :\implies \dfrac{143.092 \times3.60×10^{23 }}{6.02×10^{23}}[/tex]

[tex]\qquad[/tex] [tex]\sf :\implies \dfrac{143.092 \times3.60×\cancel{10^{23 }}}{6.02×\cancel{10^{23}}}[/tex]

[tex]\qquad[/tex] [tex]\pink{:\implies\bf 85.57 g}[/tex]

Oseni

The number of grams in 3.60 x 10^23 formula units of CU2O would be 85.54 grams

Avogadro's constant

1 mole of any substance contains 6.022 x 10^23 atoms

In this case, the number of moles in 3.60 x 10^23 units of CU2O would be:

           3.60 x 10^23/6.022 x 10^23  = 0.6 mole  

Mass of 0.6 mole CU2O = 0.6 x 143.09

                                        = 85.54 grams

More on Avogadro's constant can be found here:   https://brainly.com/question/17818186