leejawchitrakar2020
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In the given figure, BAC = 90° and ABC = 45°. Prove that: AB = AC. ​

In The Given Figure BAC 90 And ABC 45 Prove That AB AC class=

Sagot :

XxMassomestbacchixX

Answer:

By angle sum property:

BAC+ABC+BCA=180°

90°+45°+x=180°

135°+x=180°

x=45°=BCA

since BCA=ABC= 45° each

therefore,

[tex]AB=AC \\ (isosceles \: triangle \: \\ theorem)[/tex]

Hope it helps you<3

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