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If 2.80 moles of H₂ and 1.55 moles of O₂ react how many moles of H₂O can be produced in the reaction below?
2 H₂(g) + O₂(g) → 2 H₂O(g)

Sagot :

According to reaction

  • 2 moles of H2 and 1 mol of O_2 produces 2 mol H2O
  • 3 mols of reactants produces 2 moles of H_2O
  • 1 mol of reactants produces 2/3=0.6 mol.of H_2O
  • Mols of reactants=2.8+1.55=4.35

Mols of H_2O

[tex]\\ \tt\rightarrowtail 4.35(0.6)[/tex]

[tex]\\ \tt\rightarrowtail 2.61mol[/tex]

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