Answered

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A town's population is currently 100,000 people. The mayor discovered that the population is declining at a rate of 3% annually. If this rate continues, what will the population
of the town be in 4 years? Round your answer to the nearest whole number.
88,529 people
91,267 people
O 97,000 people
112,551 people

Sagot :

irunthepaint

Answer:

88,529 people

Step-by-step explanation:

if the towns population is 100,000

%10 is 10,000

meaning %1 = 1,000

1,000 x 3 = 3,000

3,000 = %3

3,000 x 4 (because its 4 years)

= 12,000

100,000 - 12,000 = 88,000

rounding it to 88,529

The population of the town after 4 years will be 88,529 people. The correct option is A.

What is exponential growth or decay function?

Consider the function:

y= a(1 ± r)ˣ

where m is the number of times this growth/decay occurs, a = initial amount, and r = fraction by which this growth/decay occurs.

  • If there is a plus sign, then there is exponential growth happening by r fraction or 100r %
  • If there is a negative sign, then there is exponential decay happening by r fraction or 100r %

Given that the town's population is currently 100,000 people, which is declining at a rate of 3%. Therefore, the population of the town after a period of 4 years will be,

Population after 4 years = P (1 - r)ⁿ

                                        = 100,000 × (1 - 0.03)⁴

                                        = 88,529.281 ≈ 88,529 people

Hence, the population of the town after 4 years will be 88,529 people.

Learn more about Exponential Growth and Decay here:

https://brainly.com/question/2193820

#SPJ5

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