[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]
Length of plot including the path :
- 125 + (3.5 × 2)= 125 + 7 = 132
width of plot including the path :
- 80 + (3.5 × 2) = 80 + 7 = 87
Now, the Area of plot including the path is :
[tex] \large \boxed{ \sf length \times width}[/tex]
[tex]\qquad \sf \dashrightarrow \: 132 \times 87[/tex]
[tex]\qquad \sf \dashrightarrow \: 11484 \:m {}^{2} [/tex]
The actual Area of the plot (excluding the path) was ;
[tex]\qquad \sf \dashrightarrow \: 125 \times 80[/tex]
[tex]\qquad \sf \dashrightarrow \: 10000 \: m {}^{2} [/tex]
So, the Area of path is ~
[tex]\qquad \sf \dashrightarrow \: 11484 - 10000[/tex]
[tex]\qquad \sf \dashrightarrow \: 1484 \: m {}^{2} [/tex]
Now, cost of grovelling it up at the 8.50 rupees per m² is ~
[tex]\qquad \sf \dashrightarrow \: 1484 \times 8.5[/tex]
[tex]\qquad \sf \dashrightarrow \: ₹ \: 12,614[/tex]
