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Sagot :
The work done on the gas during this process if the final pressure is 456 kPa is; -82.8 kJ
Workdone in Thermodynamics
We are given;
The initial pressure; P₁ = 96 kPa
Final Pressure; P₂ = 456 kPa
The gas is compressed according to;
p = aV + b
where;
a = -1200 kPa/m³
b = 600 kPa
Thus, at initial pressure P₁ = 96 kPa;
96 = -1200V₁ + 600
1200V₁ = 600 - 95
1200V₁ = 505
V₁ = 505/1200
V₁ = 0.42 m³
At Final Pressure P₂ = 456 kPa;
456 = -1200V₂ + 600
1200V₂ = 600 - 456
1200V₂ = 144
V₂ = 144/1200
V₂ = 0.12 m³
Formula for the workdone during the process is;
W_out = ¹/₂(P₁ + P₂)(V₂ - V₁)
W_out = ¹/₂(96 + 456)(0.12 - 0.42)
W_out = -82.8 kJ
Read more about workdone in thermodynamics at; https://brainly.com/question/12641937
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