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h(x)=
⎩
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎨
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎧
x
3
x
24
−1
(x−1)(x+3)
,
,
,
x∈(−∞,0]
x∈(0,8]
x∈(8,∞)
h
(
−
3
)
=
h(−3)=h, left parenthesis, minus, 3, right parenthesis, equals
