Varible combination that would produce the biggest force of impact on the egg (E). Small time of impact and large speed at impact.
Introduction
Hi ! This problem is the application of the impulse to the change in momentum. Impulse is the total force applied in a certain time interval. Impulses can cause a change of momentum, because momentum itself is a mass that is affected by the velocity of an object. We know that velocity is a vector quantity easy to change its direction. The relationship between impulse and change in momentum is formulated by :
[tex] \sf{I = \Delta p} [/tex]
[tex] \sf{F \cdot \Delta t = (m \cdot v') - (m \cdot v)} [/tex]
[tex] \boxed{\sf{\bold{F \cdot \Delta t = m (v' -v)}}} [/tex]
With the following condition :
- I = impulse that given (N.s)
- [tex] \sf{\Delta p} [/tex] = change of momentum (kg.m/s)
- F = force that given (N)
- m = mass of the object (kg)
- v = initial velocity (m/s)
- v' = final velocity (m/s)
- [tex] \sf{\Delta t} [/tex] = interval of the time (s)
Explanation
In this case, to produce a great force, then here, we refine the formula again to:
[tex] \sf{F \cdot \Delta t = m (v' -v)} [/tex]
[tex] \boxed{\sf{F = \frac{m (v' -v)}{\Delta t}}} [/tex]
Remember, when the result is a comparison, then the numerator part will be proportional to the force. The number that is the denominator will have an inversely proportional value. For this reason, if you want a great force, then:
- Increase the mass of the egg or choose a heavier egg, this is because the mass will be proportional to the force.
- Increase the change of velocity, this occurs because the change in velocity of the egg is also proportional to the force.
- Reduce the time interval (you can throw it at close range), this happens because the value of time is inversely proportional to the value of the force.
Conclusion
Varible combination that would produce the biggest force of impact on the egg (E). Small time of impact and large speed at impact.
