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Sagot :
Step-by-step explanation:
it is an exponential function but u can solve it by using logarithm so the answer is 2
Answer:
[tex]x=2[/tex]
Step-by-step explanation:
[tex]2^{3-2x} =\frac{1}{2}[/tex]
taking ln on both the sides.
[tex]3-2x ln2^{} =ln\frac{1}{2}[/tex]
[tex]3-2x = \frac{ln(1/2)}{ln(2)}[/tex]
[tex]3-2x=-1[/tex]
[tex]-2x = -1-3[/tex]
[tex]-2x=-4[/tex]
[tex]x=-4/-2[/tex]
[tex]x=2[/tex]
OR
[tex]2^{3-2x} =\frac{1}{2}[/tex]
[tex]2^{3-2x} =2^{-1}[/tex] ............... 2 gets cancelled on both sides
[tex]{3-2x} ={-1}[/tex]
[tex]{-2x} ={-1-3}[/tex]
[tex]-2x=-4[/tex]
[tex]x=-4/-2[/tex]
[tex]x=2[/tex]
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