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Pls help
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Sagot :

Step-by-step explanation:

it is an exponential function but u can solve it by using logarithm so the answer is 2

View image ruthamedie4

Answer:

[tex]x=2[/tex]

Step-by-step explanation:

[tex]2^{3-2x} =\frac{1}{2}[/tex]

taking ln on both the sides.

[tex]3-2x ln2^{} =ln\frac{1}{2}[/tex]

[tex]3-2x = \frac{ln(1/2)}{ln(2)}[/tex]

[tex]3-2x=-1[/tex]

[tex]-2x = -1-3[/tex]

[tex]-2x=-4[/tex]

[tex]x=-4/-2[/tex]

[tex]x=2[/tex]

OR

[tex]2^{3-2x} =\frac{1}{2}[/tex]

[tex]2^{3-2x} =2^{-1}[/tex] ............... 2 gets cancelled on both sides

[tex]{3-2x} ={-1}[/tex]

[tex]{-2x} ={-1-3}[/tex]

[tex]-2x=-4[/tex]

[tex]x=-4/-2[/tex]

[tex]x=2[/tex]

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