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Can someone help me solve for x?

Can Someone Help Me Solve For X class=

Sagot :

[tex] \sin(x) = \frac{73}{83} \\ [/tex]

[tex] \sin(x) = 0.8795[/tex]

[tex]x = 61.59 \: \: (Approximately )[/tex]

Thus :

[tex]x = 61.6 \: degrees[/tex]

Answer:

x ≈ 61.6°

Step-by-step explanation:

Using the sine ratio in the right triangle

sin x = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{wx}{vx}[/tex] = [tex]\frac{73}{83}[/tex] , then

x = [tex]sin^{-1}[/tex] ( [tex]\frac{73}{83}[/tex] ) ≈ 61.6° ( to the nearest tenth )

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