Answered

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Solve for x round to the nearest tenth of degree if u have too

Solve For X Round To The Nearest Tenth Of Degree If U Have Too class=

Sagot :

Answer:

x= ~37.4 degrees

there are lots of ways to solve this triangle

solve with law of sine:

i think i briefly explained it in your last question

im thinking for this one we will solve for measure of angle E then subtract it and 90 from 180

180-90-angle E= x

Pythagorean them for side EG

2.6^2 +3.4^2 = (EG)^2

EG= ~4.28

apply law of sine

call measure angle e =a

3.4 /sin of a= 4.28 /sin 90

3.4*(sin 90) = 4.28* (sin of a)

/////sin90=1

3.4 = 4.28* (sin of a)

3.4/ 4.28 = (sin of a)

sin of a= ~0.7944

do sin inverse to get value of a

a= 52.5986 degrees

180-90-a= x

180-90-52.5986=x

x=37.4014

x= ~37.4 degrees

hope this helps !!

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