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Sagot :
[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$900\\ r=rate\to 4.75\%\to \frac{4.75}{100}\dotfill &0.0475\\ n= \begin{array}{llll} \textit{times it compounds per year} \end{array}\dotfill &1\\ t=years\dotfill &9 \end{cases} \\\\\\ A=900\left(1+\frac{0.0475}{1}\right)^{1\cdot 9}\implies A=900(1.0475)^9\implies A\approx 1366.6[/tex]
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