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Sagot :
[tex]0.3=\frac{3}{10}\\\\\frac{1}{3}=\frac{1\cdot3}{3\cdot3}=\frac{3}{9}\\\\\frac{3}{10} < \frac{3}{9}\\\\therefore\ \boxed{\frac{1}{3} > 0.3\to\ \frac{1}{3}\ is\ bigger\ than\ 0.3}[/tex]
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