How much energy (in Joules) is required to convert 80 grams of ice at −46 °C to liquid water at 29 °C?

(The specific heat of ice = 2.10 J/g°C; the specific heat of water = 4.184 J/g°C; the heat of fusion = 333 J/g°C).

Question

05-02-2022
Chemistry

Answered

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How much energy (in Joules) is required to convert 80 grams of ice at −46 °C to liquid water at 29 °C?

(The specific heat of ice = 2.10 J/g°C; the specific heat of water = 4.184 J/g°C; the heat of fusion = 333 J/g°C).

Sagot :

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