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A person lifts a package weighing 23 Kg. If she lifts it 2.8 m off the floor, what work has she done?

Sagot :

MDKPfromIDN

So, the work done by her is 631.12 J.

Introduction

Hello ! I will help you regarding energy and its transformation. In this case, it's the use of energy from the lifter to be equivalent to potential energy, because the box undergoes a change in height and the potential energy specializes at a certain height. Work (W) due to change in potential energy ([tex] \sf{\Delta PE} [/tex]) can be realized in the equation :

[tex] \sf{W = \Delta PE} [/tex]

[tex] \sf{W = m \cdot g \cdot h_2 - m \cdot g \cdot h_2} [/tex]

[tex] \boxed{\sf{\bold{W = m \cdot g \cdot (h_2 - h_1)}}} [/tex]

With the following condition :

  • W = work (J)
  • m = mass of the objects (kg)
  • [tex] \sf{h_2} [/tex] = final height of object (m)
  • [tex] \sf{h_1} [/tex] = initial height of object (m)
  • g = acceleration of the gravity (m/s²)

Problem Solving

We know that :

  • m = mass of the objects = 23 kg
  • [tex] \sf{h_2} [/tex] = final height of object = 2.8 m
  • [tex] \sf{h_1} [/tex] = initial height of object = 0 m
  • g = acceleration of the gravity = 10 m/s²

What was asked :

  • W = work = ... J

Step by Step :

[tex] \sf{W = m \cdot g \cdot (h_2 - h_1)} [/tex]

[tex] \sf{W = 23 \cdot 9.8 \cdot (2.8 - 0)} [/tex]

[tex] \sf{W = 23 \cdot 9.8 \cdot 2.8} [/tex]

[tex] \boxed{\sf{W = 631.12 \: J}} [/tex]

So, the work done by her is 631.12 J.

See More :

  • Another example of calculating the energy required to lift an object https://brainly.com/question/26487284
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