quentinanton
Answered

Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Factor completely .
4u^2 - 100

Factor Completely 4u2 100 class=

Sagot :

jacob193

Answer:

[tex]4\, (u + 5)\, (u - 5)[/tex].

Step-by-step explanation:

Make use of the fact that the difference of two perfect squares, [tex](x^{2} - y^{2})[/tex], could be rewritten as a product of the form [tex](x + y)\, (x - y)[/tex]. That is:

[tex]x^{2} - y^{2} = (x + y)\, (x - y)[/tex].

In this question, the two squares are [tex](2\, u)^{2}[/tex] and [tex]10^{2}[/tex], respectively. Thus:

[tex]\begin{aligned}& 4\, u^{2} - 100 \\=\; & (2\, u)^{2} - (10)^{2} \\ =\; & (2\, u + 10) \, (2\, u - 10) \end{aligned}[/tex].

Simplify this expression even further:

[tex]\begin{aligned} & (2\, u + 10) \, (2\, u - 10) \\ =\; & (2\, (u + 5))\, (2\, (u - 5)) \\ =\; & 4\, (u + 5)\, (u - 5)\end{aligned}[/tex].

StayAliveFren

Answer:

4(u - 5)(u + 5)

Step-by-step explanation:

We have the expression, [tex]4u^2-100[/tex]

Factor out 4: [tex]4(u^2-25)[/tex]

25 can be written as [tex]5^2[/tex]

Use difference of squares property: [tex]a^2-b^2=(a-b)(a+b)[/tex]

[tex]4(u^2-5^2)[/tex]

= [tex]4(u-5)(u+5)[/tex]

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.