dwayneruffin23
Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

the problem is in the picture ​

The Problem Is In The Picture class=

Sagot :

Intriguing456

Answer:

x = 3 or 7

Step-by-step explanation:

Solve by completing the square:

[tex]x^2 - 10x + 1 = -20[/tex]

First, move the constants to one side:

[tex]x^2 - 10x = -21[/tex]

Then, add [tex](\frac{-10}{2})^2[/tex] to both sides to make the right a perfect square trinomial, which is easy to factor:

[tex]x^2 - 10x + (\frac{-10}{2})^2 = -21 + (\frac{-10}{2})^2[/tex]

Simplify and Factor:

[tex]x^2 - 10x + 25 = -21 + 25[/tex]

[tex](x - 5)^2 = 4[/tex]

Finally, square root both sides using the even roots property:

[tex]\sqrt{(x - 5)^2} = \sqrt{4}[/tex]

x - 5 = ± 2

x = 5 ± 2

x = 3   or   x = 7

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.