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HELP ITS URGENt !!!!!

HELP ITS URGENt class=

Sagot :

Answer:

Exact Value:  [tex]\sqrt{28}[/tex]

Approximate Value: 5.29

Step-by-step explanation:

[] The Pythagorean theorem is [tex]a^{2} +b^{2} =c^{2}[/tex]

-> a and b are the legs of the triangle

-> c is the hypotenuse

[] We can plug in our known values, 6 and 8, then solve for UW.

-> Let 6 be a, UW be b, and 8 be c

[Given]

[tex]a^{2} +b^{2} =c^{2}[/tex]

[Plug-in]

[tex]6^{2} +b^{2} =8^{2}[/tex]

[Square 6 and 8]

[tex]36 +b^{2} =64[/tex]

[Subtract 36 from both sides]

[tex]b^{2} =28[/tex]

[Take the square root of both sides]

b = [tex]\sqrt{28}[/tex]

-> The square and square root "cancel each other out"

[]  [tex]\sqrt{28}[/tex] is the exact value. The approximate value is 5.29 because the square root of 28 is equal to around 5.29

Have a nice day! Please keep in mind they may be looking for something different with regards to the exact/approximate values, but hopefully you can figure it out with the answer I have given.

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

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