Answered

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Solve for x round to the nearest tenth of degree if necessary

Solve For X Round To The Nearest Tenth Of Degree If Necessary class=

Sagot :

Answer:

x = 1 degree

Step-by-step explanation:

Using the Pythagorean theorem, [tex]a^{2} + b^{2} + c^{2}[/tex] we can find the unknown side then use SOHCAHTOA to find the unknown angle

First step:

[tex]a^{2} + b^{2} = c^{2} \\45^{2} + 92^{2} = c^{2} \\2025 + 8464 = c^{2} \\10489 = c^{2} \\[/tex]

Take the square root of both sides

[tex]\sqrt{10489} = \sqrt{c^{2} } \\102.4 = c[/tex]

Now to find the angle use SOHCAHTOA

Cosine = [tex]\frac{Adjacent}{Hypotenuse}[/tex] (The side we found is adjacent)(Hypotenuse is the longest side)

            = [tex]\frac{102.4}{92}[/tex]

             = 0.999

Approximately 1 degree.

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