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Dhabitah, a 60 kg diver is positioned so that her radius of gyration is 0.5 m as she leaves the board with an angular velocity of 4 rads-1. Compute Dhabitah’s angular velocity when she assumes a tuck position, altering her radius of gyration to 0.25 m. Explain how the diver applied the conservation of angular momentum to perform a somersault.​

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The final angular velocity of Dhabitah is 16 rad/s.

Conservation of angular momentum

The principle of conservation of angular momentum states the total angular momentum of an isolated system is constant.

The final angular velocity  

The final angular velocity of Dhabitah is calculated by applying the principle of conservation of angular momentum as follows;

[tex]I_1 \omega _1 = I_2 \omega _2\\\\(Mr_1^2 )\omega _1 = (Mr_2^2) \omega_2\\\\r_1^2 \omega_1 = r_2^2 \omega_2 \\\\\omega _2 = \frac{r_1^2\omega _1}{r_2^2}\\\\ \omega _2 = \frac{0.5^2 \times 4}{0.25^2} \\\\\omega_2 = 16 \ rad/s[/tex]

The diver applied the conservation of angular momentum to perform the somersault because he understood that the initial angular momentum is equal to final angular momentum.

Learn more about conservation of angular momentum here: https://brainly.com/question/7538238

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