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A student, adds 136.92 g of sucrose (FW = 342.31) to exactly 400.0 mL of dH2O. The total solution volume increased to 420.0 mL after the sucrose was dissolved and the solution was thoroughly mixed. What is the molarity of the final solution?

Sagot :

batolisis

The molarity of the final solution is : 0.953 M

Given data :

mass of sucrose = 136.92 g

volume of solvent= 400ml

Total volume of solution = 420 ml

First step : Determine moles of sucrose

Moles of sucrose = mass / molar mass

                             = 136.92 / 342.31

                             = 0.40 mol

molarity of final solution = 0.40  / 0.420  = 0.953 M.

Hence we can conclude that The molarity of the final solution is : 0.953 M

Learn more about molarity : https://brainly.com/question/17138838

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