find the vertex of function given below y=x^2-x+1

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06-02-2022
Mathematics

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find the vertex of function given below y=x^2-x+1

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muqadasbano064 muqadasbano064 · Answer 1 · 2022-02-06T03:16:16-05:00

muqadasbano064 muqadasbano064

06-02-2022

Answer:

The formula for the Axis of symmetry is -b/2a. Which is -(-2)/2(1) = 2/2 = 1. The axis of symmetry is the X of the vertex, so just plug the 1 into the equation. So the Y= 0, so the vertex is (1 , 0)

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