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The overall reaction taking place is shown in the equation below

2NaCl --> 2Na + Cl2

When carrying out the reaction 120Kg of sodium chloride was found to produce 38.05 Kg sodium.

Calculate the maximum possible mass of sodium that could be produced and use this figure to calculate the percent yield of this reaction

Sagot :

Eduard22sly

A. The maximum possible mass of sodium that can be produced is 47.18 Kg

B. The percentage yield of the reaction is 80.6%

Determination of the mass of NaCl and Na

We'll begin by calculating the mass of NaCl that reacted and the mass of Na obtained from the balanced equation.

2NaCl –> 2Na + Cl₂

Molar mass NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl from the balanced equation = 2 × 58.5 = 117 g = 117 / 1000 = 0.117 Kg

Molar mass of Na = 23 g/mol

Mass of Na from the balanced equation = 2 × 23 = 46 g = 46 / 1000 = 0.046 Kg

SUMMARY

From the balanced equation above,

0.117 Kg of NaCl reacted to produce 0.046 Kg of Na.

A. How to determine mass of Na produced

From the balanced equation above,

0.117 Kg of NaCl reacted to produce 0.046 Kg of Na.

Therefore,

120 Kg of NaCl will react to produce = (120 × 0.046) / 0.117 = 47.18 Kg of Na

Thus, the maximum mass of Na produced is 47.18 Kg.

B. How to determine the percentage yield

  • Actual yield = 38.05 Kg
  • Theoretical yield = 47.18 Kg
  • Percentage yield =?

Percentage yield = (Actual / Theoretical) × 100

Percentage yield = (38.05 / 47.18) × 100

Percentage yield = 80.6%

Learn more about stoichiometry:

https://brainly.com/question/14735801

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