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Sagot :
10) So here, in the first figure –
We are given a Rectangle and we know formula for perimeter of a rectangle's given
- Perimeter = 2 (Length + Width)
In case of 2nd figure a tiangle's given whose formula of Perimeter will be
- Perimeter = Sum of 3 sides
According to the question :-
↠Perimeter of rectangle = Perimeter of triangle
↠ x+3 +x+5+x+4 = 2 (x+4+x-2)
↠ 3x + 12 = 2(2x+2)
↠ 2(2x+2) = 3x + 12
↠ 4x +4 = 3x+12
↠ 4x-3x +4-12 = 0
↠ x -8 =0
↠ x = 8
- Henceforth, x will be 8 if they have same Perimeter.
Answer:
In Figure 1 :
We know that, It is a rectangle and the formula for finding the perimeter of a rectangle is :
- Perimeter = 2( Length + Breadth)
In Figure 2 :
We know that, it is a triangle and the formula for finding the perimeter of a triangle is :
- Perimeter = Sum of the three sides of the triangle.
[tex] \\ \: \: { \underline{ \underline{ \textbf{\textsf{{ According to the Question \::}{}}}}}}[/tex]
- Perimeter of the given rectangle = Perimeter of the given triangle.
[tex] \\ \sf \implies \: 2(x - 2 + x+4) = (x + 3) + (x + 4) + (x + 5)\: \: \: \: \: \: \: \\ \\ \sf \implies \: 2(2x +2) = x + 3 + x + 4 + x + 5\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf \implies \: 4x + 4 = 3x + 12 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf \implies \: 4x - 3x = 12 - 4 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf \implies \: x = 8 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\[/tex]
- Hence, The value of x must be 8 so that the figures have the same perimeter.
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