Answered

At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Let [tex]f(x)[/tex] be the function [tex]\frac{1}{x+3}[/tex]. Then the quotient [tex]\frac{f(7+h)-f(7)}{h}[/tex] can be simplified to [tex]\frac{-1}{ah+b}[/tex] for:
[tex]a=?[/tex]
[tex]b=?[/tex]

Sagot :

tqiu

Step-by-step explanation:

[tex]\frac{f(7+h)-f(7)}{h}\\=\frac{\frac{1}{(7+h)+3}-\frac{1}{7+3}}{h}\\=\frac{\frac{1}{10+h}-\frac{1}{10}}{h}\\=\frac{\frac{10-(10+h)}{10(10+h)}}{h}\\=\frac{-h}{10(10+h)h}}\\=\frac{-1}{10h+100}} \text { for h} \neq 0[/tex]

so a=10, b=100

Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.