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Two disinfectants were tested for their effectiveness against a strain of bacteria.
Disinfectant A had a clear circle with 3 mm diameter.
Disinfectant B had a clear circle with 6 mm diameter.
Calculate the difference in the bacteria-free area between disinfectant A and
disinfectant B.
e:
6.8 mm2
4.7 mm2
9.4 mm2
21.2 mm2

Sagot :

Answer: is 84.78 mm^2

Explanation:

we will first find out their areas, the area to be found is of a circle [tex]\pi[/tex]R^2

for the first one,

R=radius

pi=3.14

so,=3.14*(3mm*)^2

=28.26mm^2

for the second one

=3.14*(6mm*)^2

=113.04mm^2

their differences are equal to 113.04 - 28.26

=84.78 mm^2

Given the values that are supplied in the question, the difference in the bacteria-free area between is  21.2 mm^2.

What is disinfection?

The term disinfection has to do with the ability of the substance to inhibit the growth of organisms as seen by the area of each concentric circle.

In this case, the difference in the bacteria-free area between disinfectant A and disinfectant B is;

3.142 * (6/2)^2 - 3.142 * (3/2)^2

= 28.3 - 7.1

=21.2 mm^2

Learn more about disinfection:https://brainly.com/question/14781146?

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