Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
for c
8x
4
−2x
3
−27x
2
+6x+9=0
Let the roots be a,−a,b,c
S
1
=a−a+b+c=−
8
−2
=
4
1
b+c=
4
1
.....(i)
S
3
=−a
2
b−abc+abc−a
2
c=−
8
6
⇒a
2
(b+c)=
4
3
.....(ii)
dividing (i) by (ii)
⇒b+c=
4
1
......(iii)
S
4
=−a
2
bc=
8
9
⇒bc=−
8
3
....(iv)
substituting b from (iii) in (i)
b(
4
1
−b)=−
8
3
4
b−4b
2
=−
8
3
2b−8b
2
=3
8b
2
−2b−3=0
8b
2
+4b−6b−3=0
4b(2b+1)−3(2b+1)=0
(4b−3)(2b+1)=0
⇒b=
4
3
,−
2
1
substituing b in (iv)
⇒c=−
2
1
,
4
3
S
2
=a(−a)+(−a)(b)+bc+ca=
8
−27
⇒−a
2
−ab+bc+ac=
8
−27
The value of s
4
is not satisfied for b=−
2
1
So the roots of the equation are
3
,−
3
,
4
3
,−
2
1
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.
