Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
- Width be x
- Length be 2x
ATQ
[tex]\\ \tt\hookrightarrow Perimeter=88[/tex]
[tex]\\ \tt\hookrightarrow 2(x+2x)=88[/tex]
[tex]\\ \tt\hookrightarrow 2(3x)=88[/tex]
[tex]\\ \tt\hookrightarrow 6x=88[/tex]
[tex]\\ \tt\hookrightarrow 3x=44[/tex]
[tex]\\ \tt\hookrightarrow x=44/3\approx 15[/tex]
- Width=15
- Length=2(15)=30
Answer:
- L = 88/3 units
- W = 44/3 units
Step-by-step explanation:
We know that:
- Perimeter of rectangle: 88
- L = 2w
Solution:
- 2(L) + 2(w) = 88 units
- => 2(2w) + 2(w) = 88 units
- => 4w + 2w = 88 units
- => 6w = 88 units
- => w = 88/6 units
- => L = 2w
- => L = 2(14 2/3)
- => L = 2(44/3)
- => L = 88/3 units
Hence, the dimensions of the rectangle is:
- L = 88/3 units
- W = 44/3 units
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
