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Sagot :
- Width be x
- Length be 2x
ATQ
[tex]\\ \tt\hookrightarrow Perimeter=88[/tex]
[tex]\\ \tt\hookrightarrow 2(x+2x)=88[/tex]
[tex]\\ \tt\hookrightarrow 2(3x)=88[/tex]
[tex]\\ \tt\hookrightarrow 6x=88[/tex]
[tex]\\ \tt\hookrightarrow 3x=44[/tex]
[tex]\\ \tt\hookrightarrow x=44/3\approx 15[/tex]
- Width=15
- Length=2(15)=30
Answer:
- L = 88/3 units
- W = 44/3 units
Step-by-step explanation:
We know that:
- Perimeter of rectangle: 88
- L = 2w
Solution:
- 2(L) + 2(w) = 88 units
- => 2(2w) + 2(w) = 88 units
- => 4w + 2w = 88 units
- => 6w = 88 units
- => w = 88/6 units
- => L = 2w
- => L = 2(14 2/3)
- => L = 2(44/3)
- => L = 88/3 units
Hence, the dimensions of the rectangle is:
- L = 88/3 units
- W = 44/3 units
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