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Hess’s law
A -> B Delta H= +30kJ
B -> C Delta H= +60kJ
A.) Use Hess’s law to calculate the enthalpy change for the reaction A -> C
B.) Construct an enthalpy diagram for substances A, B, and C and show how Hess’s law applies.


Hesss Law A Gt B Delta H 30kJ B Gt C Delta H 60kJ A Use Hesss Law To Calculate The Enthalpy Change For The Reaction A Gt C B Construct An Enthalpy Diagram For S class=

Sagot :

From the statement of Hess' law, the enthalpy of the reaction A---> C is +90 kJ

What is Hess' law?

Hess' law of constant heat summation states that for a multistep reaction, the standard enthalpy of reaction is always constant and is independent of the pathway or intermediate routes taken.

From Hess' law, the enthalpy change for the reaction A ----> C is calculated as follows:

A---> C = A ---> B + B ---> C

ΔH of A---> C = 30 kJ + 60 kJ

ΔH = 90 kJ

Therefore, the enthalpy of the reaction A---> C is +90 kJ

The above reaction A---> C can be shown in the enthalpy diagram below:

A -------------------> C (ΔH = +90 kJ)

\ /

\ / (ΔH = +60 kJ)

(ΔH = +30 J) \ /

> B

Learn more about enthalpy and Hess law at: https://brainly.com/question/9328637

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