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solve
2x-1=3y
5(2x-1)+y=32

Sagot :

2x-1=3y would be 1/-3
For 5 (2x-1)+y=32 would be 37/10, if its wrong, forgive me

Answer:

x = 7/2 (3 1/2), y = 2

Step-by-step explanation:

  • [tex]2x - 1 = 3y[/tex]
  • [tex]10x + y -5=32[/tex]

Step 1: Solve 10x + y - 5 for y.

  • [tex]10x+y-5-10x=32-10x[/tex] (subtract 10x from both sides)
  • [tex]y - 5 = -10x + 32[/tex]
  • [tex]y-5+5=-10x+32+5[/tex] (add 5 to both sides)
  • [tex]y = -10x + 37[/tex]

Step 2: Substitute -10x + 37 for y in 2x - 1 = 3y.

  • [tex]2x-1=3(-10x+37)[/tex]
  • [tex]2x - 1 = -30x + 111[/tex] (simplify both sides)
  • [tex]2x-1+30x=-30x+111+30x[/tex] (add 30x to both sides)
  • [tex]32x-1=111[/tex]
  • [tex]32x-1+1=111+1[/tex] (add 1 to both sides)
  • [tex]32x = 112[/tex]
  • [tex]32x/32 = 112/32[/tex] (divide both sides by 32)
  • [tex]x = 7/2[/tex]

Step 3: Substitute 7/2 for x in y = -10x +37.

  • [tex]y=-10(7/2) +37[/tex]
  • [tex]y = -35 + 37[/tex] (simplify both sides)
  • [tex]y = 2[/tex] (simplify both sides

Have a lovely rest of your day/night, and good luck with your assignments! ♡

 ~ ren

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