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Sagot :
2x-1=3y would be 1/-3
For 5 (2x-1)+y=32 would be 37/10, if its wrong, forgive me
For 5 (2x-1)+y=32 would be 37/10, if its wrong, forgive me
Answer:
x = 7/2 (3 1/2), y = 2
Step-by-step explanation:
- [tex]2x - 1 = 3y[/tex]
- [tex]10x + y -5=32[/tex]
Step 1: Solve 10x + y - 5 for y.
- [tex]10x+y-5-10x=32-10x[/tex] (subtract 10x from both sides)
- [tex]y - 5 = -10x + 32[/tex]
- [tex]y-5+5=-10x+32+5[/tex] (add 5 to both sides)
- [tex]y = -10x + 37[/tex]
Step 2: Substitute -10x + 37 for y in 2x - 1 = 3y.
- [tex]2x-1=3(-10x+37)[/tex]
- [tex]2x - 1 = -30x + 111[/tex] (simplify both sides)
- [tex]2x-1+30x=-30x+111+30x[/tex] (add 30x to both sides)
- [tex]32x-1=111[/tex]
- [tex]32x-1+1=111+1[/tex] (add 1 to both sides)
- [tex]32x = 112[/tex]
- [tex]32x/32 = 112/32[/tex] (divide both sides by 32)
- [tex]x = 7/2[/tex]
Step 3: Substitute 7/2 for x in y = -10x +37.
- [tex]y=-10(7/2) +37[/tex]
- [tex]y = -35 + 37[/tex] (simplify both sides)
- [tex]y = 2[/tex] (simplify both sides
Have a lovely rest of your day/night, and good luck with your assignments! ♡
~ ren
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