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Sagot :
[tex]\displaystyle\bf\\12\frac{1}{5}-4\frac{1}{5}=\\\\=\frac{12\times5+1}{5}-\frac{4\times5+1}{5}=\\\\=\frac{60+1}{5}-\frac{20+1}{5}=\\\\=\frac{61}{5}-\frac{21}{5}=\\\\=\frac{61-21}{5}=\frac{40}{5}=\boxed{\bf8}[/tex]
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